(x+3)(x+5)(x+6)(x+10)=2x^2

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Solution for (x+3)(x+5)(x+6)(x+10)=2x^2 equation: 



(x+3)(x+5)(x+6)(x+10)=2x^2

We move all terms to the left:

(x+3)(x+5)(x+6)(x+10)-(2x^2)=0

determiningTheFunctionDomain
-2x^2+(x+3)(x+5)(x+6)(x+10)=0

We multiply parentheses ..

-2x^2+(+x^2+5x+3x+15)(x+6)(x+10)=0

We multiply parentheses ..

-2x^2+(+x^2+5x+3x+15)(+x^2+10x+6x+60)=0

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